Position and displacement
Position is where you are; displacement is how your position changed — a vector, not the distance travelled.
In this lesson
- Position is where you are; displacement is how your position changed — a vector, not the distance travelled.
Run a 400 m lap: distance 400 m, displacement zero. Displacement only cares about start and end.
Position x(t) locates the body on the axis. Displacement Δx = x₂ − x₁ is the change in position — a vector with sign. Distance is the total path length, always positive, and generally larger than |displacement|.
On a straight line, sign carries direction: +x and −x. In every kinematics problem, first fix the positive direction and keep it consistent.
Displacement as change in position
Worked example
A particle moves from x = 3 m to x = −5 m. Find the displacement and the distance if it went straight.
- Δx = x₂ − x₁ = −5 − 3 = −8 m.
- Distance along the straight path = |Δx| = 8 m.
Answer: Δx = −8 m; distance 8 m.
Transcript (0 min)
WEBVTT 1 00:00:00.000 --> 00:00:05.000 Position and displacement — FemtoLearn. 2 00:00:05.000 --> 00:00:15.000 Position is where you are; displacement is how your position changed — a vector, not the distance travelled.
Frequently asked
Can displacement exceed distance?
Never. Distance ≥ |displacement|.
Practice
Free · 4 questions with full solutions- Q1 · Numerical · difficulty 2/5
A body moves with v = 10 m/s for 3 s, then v = 5 m/s for 2 s in the same direction. Find the total distance.
- Q2 · Numerical · difficulty 2/5
A body starts from rest with a = 4 m/s². Find the displacement in the 5th second.
- Q3 · Numerical · difficulty 2/5
A body starts from rest and accelerates uniformly at 9.5 m/s². Find the displacement in the 8th second of its motion.
- Q4 · Numerical · difficulty 2/5
The acceleration of a body starting from rest is a = 2 m/s² for 4 s, then zero for 2 s. Find its velocity at t = 6 s.