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Projectile on an inclined plane

Free notes · JEE Main Physics

Formulas

Rincline=2u2cos⁡θsin⁡(θ−α)gcos⁡2αR_{incline} = \frac{2u^2\cos\theta\sin(\theta-\alpha)}{g\cos^2\alpha}

Range along an incline

Worked example

For a fixed launch speed, the horizontal range of a projectile is maximum when the launch angle is:

  1. R = v0² sin 2θ / g
  2. R is maximum when sin 2θ = 1, i.e. 2θ = 90°, so θ = 45°

Answer: 45°