← Back to lesson

Relative motion of two projectiles

Free notes · JEE Main Physics

Formulas

r⃗rel(t)=r⃗0+v⃗rel t\vec{r}_{rel}(t) = \vec{r}_0 + \vec{v}_{rel}\, t

Relative position of projectiles

Worked example

For a fixed launch speed, the horizontal range of a projectile is maximum when the launch angle is:

  1. R = v0² sin 2θ / g
  2. R is maximum when sin 2θ = 1, i.e. 2θ = 90°, so θ = 45°

Answer: 45°